Evaluate ∫ 4ˣ dx.
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
11. Integrals of Inverse, Exponential, & Logarithmic Functions
Integrals of Exponential Functions
Problem 7.3.49
Textbook Question
37–56. Integrals Evaluate each integral.
∫ eˣ/(36 – e²ˣ), x < ln 6
Verified step by step guidance1
Identify the integral to solve: \(\int \frac{e^x}{36 - e^{2x}} \, dx\) with the condition \(x < \ln 6\).
Recognize that the denominator can be rewritten as a difference of squares: \$36 - e^{2x} = (6)^2 - (e^x)^2$.
Use substitution by letting \(u = e^x\). Then, compute \(du = e^x \, dx\), which implies \(dx = \frac{du}{u}\).
Rewrite the integral in terms of \(u\): \(\int \frac{u}{36 - u^2} \cdot \frac{du}{u} = \int \frac{1}{36 - u^2} \, du\).
Recognize the integral \(\int \frac{1}{a^2 - u^2} \, du\) and recall the formula for this type of integral, which involves partial fractions or inverse hyperbolic functions, then proceed accordingly.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Integration by Substitution
Integration by substitution is a method used to simplify integrals by changing variables. It involves identifying a part of the integrand as a new variable, which transforms the integral into a simpler form. This technique is especially useful when the integral contains a composite function.
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Properties of Exponential Functions
Understanding exponential functions, such as eˣ and e²ˣ, is crucial for manipulating and simplifying expressions within integrals. Knowing how to handle their derivatives and algebraic properties helps in recognizing substitution candidates and simplifying the integrand.
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Domain Restrictions and Their Impact
The condition x < ln 6 restricts the domain of the integral, ensuring the denominator 36 – e²ˣ remains positive and the integral is defined. Recognizing domain restrictions helps avoid undefined expressions and guides the choice of substitution and integration limits.
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