69. Comparing volumes Let R be the region bounded by y = sin x and the x-axis on the interval [0, π]. Which is greater, the volume when R is revolved about the x-axis, or the volume when R is revolved about the y-axis?
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
9. Graphical Applications of Integrals
Introduction to Volume & Disk Method
Problem 6.R.42b
Textbook Question
Two methods The region R in the first quadrant bounded by the parabola y = 4-x² and coordinate axes is revolved about the y-axis to produce a dome-shaped solid. Find the volume of the solid in the following ways:
b. Apply the shell method and integrate with respect to x.
Verified step by step guidance1
Identify the region R bounded by the parabola \(y = 4 - x^{2}\) and the coordinate axes in the first quadrant. Since we are in the first quadrant, \(x\) ranges from 0 to the point where the parabola meets the x-axis, which is found by solving \$4 - x^{2} = 0$.
Set up the shell method formula for volume when revolving around the y-axis. The volume \(V\) is given by the integral \(V = \int_{a}^{b} 2\pi \cdot (\text{radius}) \cdot (\text{height}) \, dx\), where the radius is the distance from the y-axis (which is \(x\)) and the height is the function value \(y = 4 - x^{2}\).
Determine the limits of integration \(a\) and \(b\). Since the region is bounded between \(x=0\) and the x-intercept of the parabola, \(b\) is the positive root of \$4 - x^{2} = 0\(, which is \)x=2$.
Write the integral explicitly: \(V = \int_{0}^{2} 2\pi x (4 - x^{2}) \, dx\). This integral represents the volume of the solid formed by revolving the region around the y-axis using the shell method.
To find the volume, expand the integrand and integrate term-by-term with respect to \(x\) over the interval \([0, 2]\). After integrating, evaluate the definite integral at the limits to express the volume.
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
2mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Shell Method for Volume
The shell method calculates the volume of a solid of revolution by summing cylindrical shells. Each shell's volume is approximated by its circumference times height times thickness. When revolving around the y-axis, shells are vertical slices parallel to the axis, integrated with respect to x.
Recommended video:
Finding Volume Using Disks
Setting up the Integral with Respect to x
To use the shell method with respect to x, identify the radius as the distance from the y-axis (x), the height as the function value y = 4 - x², and the thickness as dx. The integral bounds correspond to the x-values where the region exists, here from 0 to 2.
Recommended video:
Integrals of Natural Exponential Functions (e^x)
Region Bounded by the Parabola and Axes
The region R lies in the first quadrant bounded by y = 4 - x², the x-axis, and the y-axis. Understanding these boundaries helps determine the limits of integration and the shape of the solid formed when revolved around the y-axis.
Recommended video:
Properties of Parabolas
Watch next
Master Introduction to Cross Sections with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Textbook Question
9
views
