Orthogonal trajectories Use the method in Exercise 44 to find the orthogonal trajectories for the family of circles x² + y² = a²
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
13. Intro to Differential Equations
Separable Differential Equations
Problem 9.4.37b
Textbook Question
A bad loan Consider a loan repayment plan described by the initial value problem
B'(t)=0.03B−600,B(0)=40,000,
where the amount borrowed is B(0)=\$40,000, the monthly payments are \$600, and B(t) is the unpaid balance in the loan.
b. What is the most that you can borrow under the terms of this loan without going further into debt each month?
Verified step by step guidance1
Identify the differential equation given: \(B'(t) = 0.03B - 600\), where \(B(t)\) is the unpaid balance at time \(t\), and \(B(0) = 40,000\) is the initial loan amount.
Understand that the question asks for the maximum initial loan amount such that the balance does not increase over time, meaning the unpaid balance does not grow each month. This implies that the rate of change of the balance, \(B'(t)\), should be less than or equal to zero at the start (i.e., \(B'(0) \leq 0\)).
Set up the inequality using the differential equation at \(t=0\): \(B'(0) = 0.03 B(0) - 600 \leq 0\). This inequality ensures the loan balance does not increase initially.
Solve the inequality for \(B(0)\): \$0.03 B(0) \leq 600\(, which leads to \)B(0) \leq \frac{600}{0.03}$. This gives the maximum loan amount that can be borrowed without the balance increasing.
Interpret the result: the maximum loan amount is the value of \(B(0)\) found above, which ensures the loan balance will not grow over time under the given repayment plan.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Initial Value Problem (IVP)
An initial value problem involves a differential equation along with a specified value of the unknown function at a starting point. Here, B'(t) = 0.03B - 600 with B(0) = 40,000 means the rate of change of the loan balance depends on the current balance and payments, starting from $40,000 owed.
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Initial Value Problems
Solving First-Order Linear Differential Equations
This type of differential equation can be solved using integrating factors or separation of variables. It helps find the function B(t) describing the loan balance over time, which is essential to analyze how the balance changes with interest and payments.
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Solving Separable Differential Equations
Equilibrium or Steady-State Solution
The steady-state solution occurs when the loan balance stops changing, i.e., B'(t) = 0. Finding this equilibrium helps determine the maximum loan amount that can be maintained without increasing debt, by setting the growth from interest equal to the monthly payment.
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Solutions to Basic Differential Equations
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