Determine the vertices and foci of the following ellipse: $\frac{x^2}{9}+\frac{y^2}{16}=1$.

• A. Vertices: $\(\left\)(4,0\(\right\)),\(\left\)(-4,0\(\right\))$Foci: $\(\left\)(\(\sqrt\)7,0\(\right\)),\(\left\)(-\(\sqrt\)7,0\(\right\))$
• B. Vertices: $\(\left\)(0,4\(\right\)),\(\left\)(0,-4\(\right\))$Foci: $\(\left\)(0,\(\sqrt\)7\(\right\)),\(\left\)(0,-\(\sqrt\)7\(\right\))$
• C. Vertices: $\(\left\)(4,0\(\right\)),\(\left\)(-4,0\(\right\))$Foci: $\(\left\)(3,0\(\right\)),\(\left\)(-3,0\(\right\))$
• D. Vertices: $\(\left\)(0,4\(\right\)),\(\left\)(0,-4\(\right\))$Foci: $\(\left\)(0,3\(\right\)),\(\left\)(0,-3\(\right\))$

Answer: (B)