Solve the given quadratic equation by completing the square.
$x^2+3x-5=0$

• A. $x=-\(\frac\)32,x=\(\frac\)52$
• B. $x=-\(\frac\)32,x=\(\sqrt{29}\)$
• C. $x=\(\frac{-3+\sqrt{29}\)}{2},x=\(\frac{-3-\sqrt{29}\)}{2}$
• D. $x=\(\frac{3+\sqrt{29}\)}{2},x=\(\frac{3-\sqrt{29}\)}{2}$

Answer: (C)