Cancel out the common \$998!$ terms in numerator and denominator, leaving:
\[1000 \times 999\]
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above
Video duration:
1m
Play a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Factorial Definition
The factorial of a positive integer n, denoted n!, is the product of all positive integers from 1 up to n. For example, 5! = 5 × 4 × 3 × 2 × 1 = 120. Understanding this definition is essential to simplify expressions involving factorials.
When dividing factorials like n! / (n - k)!, many terms cancel out because (n - k)! is a part of n!. This allows simplification to a product of k consecutive integers starting from n downwards, making calculations easier without full expansion.
Ratios of factorials often reduce to products of a few terms. For example, 1000! / 998! equals 1000 × 999 because 998! cancels out the terms from 1 to 998 in the numerator. Recognizing this property helps evaluate large factorial expressions efficiently.