Set up the fraction and simplify by canceling common terms: \(\frac{(2n)!}{(2n - 1)!} = \frac{(2n) \times (2n - 1) \times \cdots \times 1}{(2n - 1) \times \cdots \times 1} = 2n\).
Conclude that the statement \(\frac{(2n)!}{(2n - 1)!} = 2n\) is true because the factorial terms cancel except for the factor \$2n$ in the numerator.
Therefore, the expression simplifies exactly to \$2n$, confirming the statement is correct.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Factorials and Their Properties
A factorial, denoted n!, is the product of all positive integers from 1 up to n. Understanding how factorials expand and simplify is essential, especially when dealing with ratios like (2n)! / (2n − 1)!, where many terms cancel out.
When dividing factorials such as (2n)! by (2n − 1)!, most terms cancel, leaving only the highest term, 2n. This simplification helps determine if the given expression equals 2n or not.
To test the truth of a statement involving factorials, substituting specific values of n can confirm or refute it. A single counterexample disproves the statement, while consistent results support its validity.