How does the eccentricity determine the type of conic section?
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- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
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- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
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- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
16. Parametric Equations & Polar Coordinates
Conic Sections
Problem 12.4.49
Textbook Question
39–50. Equations of ellipses and hyperbolas Find an equation of the following ellipses and hyperbolas, assuming the center is at the origin.

Verified step by step guidance1
Identify the type of conic section: Since the graph shows two branches opening left and right with vertices at (±4, 0) and foci at (±5, 0), this is a hyperbola centered at the origin with a horizontal transverse axis.
Recall the standard form of the equation of a hyperbola centered at the origin with a horizontal transverse axis: \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\).
Determine the value of \(a\): The vertices are at (±4, 0), so \(a = 4\), which means \(a^2 = 16\).
Determine the value of \(c\): The foci are at (±5, 0), so \(c = 5\), which means \(c^2 = 25\).
Use the relationship between \(a\), \(b\), and \(c\) for hyperbolas: \(c^2 = a^2 + b^2\). Substitute the known values to solve for \(b^2\): \$25 = 16 + b^2\(, then solve for \)b^2$.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Standard Equation of a Hyperbola Centered at the Origin
A hyperbola centered at the origin with a horizontal transverse axis has the equation \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \). Here, \(a\) is the distance from the center to each vertex along the x-axis, and \(b\) relates to the distance along the conjugate axis. Understanding this form is essential to write the equation from given vertices and foci.
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Relationship Between Vertices, Foci, and Parameters \(a\), \(b\), and \(c\)
For hyperbolas, \(a\) is the distance from the center to each vertex, and \(c\) is the distance to each focus. These satisfy the equation \( c^2 = a^2 + b^2 \). Knowing the coordinates of vertices and foci allows calculation of \(a\), \(c\), and subsequently \(b\), which are needed to form the hyperbola's equation.
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Foci and Vertices of Hyperbolas
Graph Interpretation and Coordinate Geometry
Interpreting the graph involves identifying key points such as vertices and foci and their coordinates. This helps in determining the values of \(a\) and \(c\) directly from the graph. Accurate reading of these points is crucial for applying the hyperbola formulas correctly.
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Intro to Polar Coordinates
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