Does a geometric series always have a finite value?
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
14. Sequences & Series
Series
Problem 10.3.87g
Textbook Question
87. Explain why or why not
Determine whether the following statements are true and give an explanation or counterexample.
g. Viewed as a function of r, the series 1 + r + r² + r³ + ⋯ takes on all values in the interval (1/2, ∞).
Verified step by step guidance1
Recall the formula for the sum of an infinite geometric series \(S = 1 + r + r^2 + r^3 + \cdots\) when \(|r| < 1\), which is given by \(S = \frac{1}{1 - r}\).
Identify the domain of \(r\) for which the series converges: the series converges only if \(|r| < 1\).
Analyze the range of the sum \(S = \frac{1}{1 - r}\) as \(r\) varies within \((-1, 1)\): as \(r\) approaches 1 from below, \(S\) grows without bound towards \(+\infty\); as \(r\) approaches \(-1\) from above, \(S\) approaches \(\frac{1}{1 - (-1)} = \frac{1}{2}\).
Conclude that the sum \(S\) takes on all values in the interval \((\frac{1}{2}, \infty)\) as \(r\) varies in \((-1, 1)\), which is the domain of convergence.
Therefore, the statement is true if we consider \(r\) restricted to \((-1, 1)\), but false if \(r\) is allowed outside this interval since the series does not converge there.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Geometric Series and Its Sum Formula
A geometric series is a sum of terms where each term is a constant ratio r times the previous term. For |r| < 1, the infinite series 1 + r + r² + r³ + ⋯ converges to 1/(1 - r). Understanding this formula is essential to analyze the values the series can take as a function of r.
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Domain and Range of the Sum Function
The sum function S(r) = 1/(1 - r) is defined for all r except r = 1, where it diverges. Its range depends on the values of r, especially considering convergence criteria. Analyzing the interval of r values that produce sums within (1/2, ∞) helps determine if the series covers that entire interval.
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Convergence Criteria for Infinite Series
For an infinite geometric series to converge, the common ratio r must satisfy |r| < 1. If |r| ≥ 1, the series diverges and does not sum to a finite value. This criterion restricts the possible sums and is crucial when evaluating whether the series can take all values in a given interval.
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Convergence of an Infinite Series
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