Skip to main content
Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 3, Problem 72b

The right-sided and left-sided derivatives of a function at a point aa are given by f+(a)=limh0+f(a+h)f(a)hf_{+}^{\(\prime\)}\(\left\)(a\(\right\))={\(\displaystyle\]\lim\)_{h\(\to\)0^{+}}{\(\frac{f(a+h)-f(a)}{h}\)}} and f(a)=limh0f(a+h)f(a)hf_{-}^{\(\prime\)}\(\left\)(a\(\right\))={\(\displaystyle\]\lim\)_{h\(\to\)0^{-}}{\(\frac{f(a+h)-f(a)}{h}\)}}, respectively, provided these limits exist. The derivative f(a)f^{\(\prime\)}\(\left\)(a\(\right\)) exists if and only if f+(a)=f(a)f_{+}^{\(\prime\)}\(\left\)(a\(\right\))=f_{-}^{\(\prime\)}\(\left\)(a\(\right\)).
Compute f+(a)f_{+}^{\(\prime\)}\(\left\)(a\(\right\)) and f(a)f_{-}^{\(\prime\)}\(\left\)(a\(\right\)) at the given point aa.
f(x)={4x2 if x12x+1 if x>1f(x)=\(\begin{cases}\)4-x^2~\(\text{if}\)~x\(\leq{1}\)\\2x+1~\(\text{if}\)~x\(\gt{1}\]\end{cases}\); a=1a=1

Verified step by step guidance
1
Identify the piecewise function given: f(x) = 4 - x^2 for x ≤ 1 and f(x) = 2x + 1 for x > 1. We need to compute the right-sided and left-sided derivatives at a = 1.
Compute the left-sided derivative f_{-}^{\(\text{prime}\)}(1) using the limit definition: f_{-}^{\(\text{prime}\)}(1) = \(\lim\)_{h \(\to\) 0^{-}} \(\frac{f(1+h) - f(1)}{h}\). Since x ≤ 1, use f(x) = 4 - x^2. Substitute f(1) = 4 - 1^2 = 3 and f(1+h) = 4 - (1+h)^2.
Simplify the expression for the left-sided derivative: f_{-}^{\(\text{prime}\)}(1) = \(\lim\)_{h \(\to\) 0^{-}} \(\frac{(4 - (1+h)^2) - 3}{h}\). Expand (1+h)^2 to get 1 + 2h + h^2, and simplify the numerator.
Compute the right-sided derivative f_{+}^{\(\text{prime}\)}(1) using the limit definition: f_{+}^{\(\text{prime}\)}(1) = \(\lim\)_{h \(\to\) 0^{+}} \(\frac{f(1+h) - f(1)}{h}\). Since x > 1, use f(x) = 2x + 1. Substitute f(1) = 3 and f(1+h) = 2(1+h) + 1.
Simplify the expression for the right-sided derivative: f_{+}^{\(\text{prime}\)}(1) = \(\lim\)_{h \(\to\) 0^{+}} \(\frac{(2(1+h) + 1) - 3}{h}\). Simplify the numerator and evaluate the limit to find f_{+}^{\(\text{prime}\)}(1).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
7m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Right-sided and Left-sided Derivatives

Right-sided and left-sided derivatives are limits that describe the behavior of a function as it approaches a specific point from the right or left, respectively. The right-sided derivative at a point 'a' is defined as the limit of the difference quotient as 'h' approaches zero from the positive side, while the left-sided derivative is defined as the limit as 'h' approaches zero from the negative side. These derivatives help determine the function's behavior near points of interest, especially at points of discontinuity.
Recommended video:
05:50
One-Sided Limits

Existence of the Derivative

A function has a derivative at a point if both the right-sided and left-sided derivatives exist and are equal at that point. This condition ensures that the function is smooth and continuous at that point, allowing for a well-defined tangent line. If the two derivatives are not equal, the function is not differentiable at that point, which can indicate a cusp, corner, or vertical tangent.
Recommended video:
03:07
Cases Where Limits Do Not Exist

Piecewise Functions

Piecewise functions are defined by different expressions based on the input value. In the context of the given question, the function is defined differently for values less than or equal to 1 and for values greater than 1. Understanding how to evaluate and differentiate piecewise functions is crucial, as the behavior of the function can change at the boundaries, affecting the calculation of derivatives at those points.
Recommended video:
05:36
Piecewise Functions