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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 10, Problem 10.8.11

11–86. Applying convergence tests Determine whether the following series converge. Justify your answers.
∑ (from k = 1 to ∞) (2k⁴ + k) / (4k⁴ − 8k)

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First, write down the general term of the series: \(a_k = \frac{2k^4 + k}{4k^4 - 8k}\).
To analyze convergence, consider the behavior of \(a_k\) as \(k\) approaches infinity. Simplify the expression by dividing numerator and denominator by the highest power of \(k\) present in the denominator, which is \(k^4\):
\[a_k = \frac{2k^4 + k}{4k^4 - 8k} = \frac{2 + \frac{1}{k^3}}{4 - \frac{8}{k^3}}.\]
Evaluate the limit of \(a_k\) as \(k \to \infty\): \(\lim_{k \to \infty} a_k = \frac{2 + 0}{4 - 0} = \frac{2}{4} = \frac{1}{2}\). Since this limit is not zero, the terms do not approach zero.
Recall the necessary condition for series convergence: if \(\lim_{k \to \infty} a_k \neq 0\), then the series \(\sum a_k\) diverges. Therefore, conclude that the series diverges.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Convergence of Infinite Series

An infinite series converges if the sequence of its partial sums approaches a finite limit. Determining convergence involves analyzing the behavior of the terms as the index grows large, ensuring the sum does not diverge to infinity or oscillate indefinitely.
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Limit Comparison Test

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