Find the exact length of the curve for .
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
1. Limits and Continuity
Finding Limits Algebraically
Problem 7.1.70
Textbook Question
Behavior at the origin Using calculus and accurate sketches, explain how the graphs of f(x) = xᵖ ln x differ as x → 0⁺ for p = 1/2, 1, and 2.
Verified step by step guidance1
First, recognize that the function is given by \(f(x) = x^{p} \ln x\), and we are interested in the behavior as \(x \to 0^{+}\). Since \(\ln x\) tends to \(-\infty\) as \(x \to 0^{+}\), the product's behavior depends on the power \(p\) of \(x\).
Rewrite the function to analyze the limit: \(f(x) = x^{p} \ln x = \frac{\ln x}{x^{-p}}\). As \(x \to 0^{+}\), \(x^{-p} \to +\infty\), so this is an indeterminate form of type \(\frac{-\infty}{+\infty}\), which suggests using L'Hôpital's Rule.
Apply L'Hôpital's Rule by setting \(g(x) = \ln x\) and \(h(x) = x^{-p}\). Compute the derivatives: \(g'(x) = \frac{1}{x}\) and \(h'(x) = -p x^{-p-1}\). Then, the limit becomes \(\lim_{x \to 0^{+}} \frac{g'(x)}{h'(x)} = \lim_{x \to 0^{+}} \frac{\frac{1}{x}}{-p x^{-p-1}}\).
Simplify the expression: \(\frac{\frac{1}{x}}{-p x^{-p-1}} = \frac{1}{x} \cdot \frac{1}{-p} \cdot x^{p+1} = -\frac{1}{p} x^{p}\). As \(x \to 0^{+}\), \(x^{p} \to 0\), so the limit is \$0\(. This shows that \)\lim_{x \to 0^{+}} x^{p} \ln x = 0\( for all \)p > 0$.
To understand how the graphs differ for \(p = \frac{1}{2}, 1,\) and \$2\(, note that the factor \)x^{p}\( approaches zero at different rates. For smaller \)p\(, \)x^{p}\( approaches zero more slowly, so the negative logarithmic term dominates more, causing the graph to dip more sharply near zero. For larger \)p\(, \)x^{p}\( goes to zero faster, so the product approaches zero more gently. Sketching these will show the curve for \)p=\frac{1}{2}\( dipping down more steeply near zero, while for \)p=2$ it approaches zero more smoothly.
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
9mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Behavior of Functions Near Zero
Understanding how functions behave as x approaches zero from the right (x → 0⁺) is crucial. This involves analyzing limits and determining whether the function approaches zero, infinity, or a finite value, which helps in sketching accurate graphs near the origin.
Recommended video:
Guided course
Zero and Negative Rules
Properties of the Natural Logarithm Function
The natural logarithm ln(x) tends to negative infinity as x approaches zero from the right. This behavior significantly influences the product xᵖ ln(x), especially since ln(x) dominates near zero, affecting the overall shape and limit of the function.
Recommended video:
Properties of Functions
Effect of the Power p in xᵖ
The exponent p controls how quickly xᵖ approaches zero as x → 0⁺. Different values of p (1/2, 1, 2) change the rate at which the product xᵖ ln(x) tends to zero or diverges, impacting the graph's slope and curvature near the origin.
Recommended video:
Intro to Power Series
Watch next
Master Finding Limits by Direct Substitution with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Multiple Choice
59
views
