Caffeine An adult consumes an espresso containing 75 mg of caffeine. If the caffeine has a half-life of 5.5 hours, when will the amount of caffeine in her bloodstream equal 30 mg?
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
0. Functions
Exponential Functions
Problem 7.2.16
Textbook Question
15–20. Designing exponential growth functions Complete the following steps for the given situation.
a. Find the rate constant k and use it to devise an exponential growth function that fits the given data.
b. Answer the accompanying question.
Population The population of Clark County, Nevada, was about 2.115 million in 2015. Assuming an annual growth rate of 1.5%/yr, what will the county population be in 2025?
Verified step by step guidance1
Step 1: Identify the given information and variables. The initial population at time \(t=0\) (year 2015) is \(P_0 = 2.115\) million. The annual growth rate is 1.5%, which can be written as a decimal \(r = 0.015\). The time elapsed from 2015 to 2025 is \(t = 10\) years.
Step 2: Recall the general form of the exponential growth function: \(P(t) = P_0 \cdot e^{k t}\), where \(k\) is the rate constant we need to find.
Step 3: Relate the given annual growth rate to the rate constant \(k\). Since the population grows by 1.5% per year, the growth factor per year is \$1 + r = 1.015\(. This corresponds to \)e^{k} = 1.015\(, so solve for \)k\( by taking the natural logarithm: \)k = \ln(1.015)$.
Step 4: Write the exponential growth function using the calculated \(k\): \(P(t) = 2.115 \cdot e^{k t}\), where \(k = \ln(1.015)\) and \(t\) is the number of years after 2015.
Step 5: To find the population in 2025, substitute \(t = 10\) into the function: \(P(10) = 2.115 \cdot e^{k \cdot 10}\). This expression gives the population in millions at the year 2025.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Exponential Growth Function
An exponential growth function models quantities that increase at a rate proportional to their current value. It is generally expressed as P(t) = P_0 * e^(kt), where P_0 is the initial amount, k is the growth rate constant, and t is time. This function is essential for predicting population changes over time.
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Rate Constant (k) in Exponential Growth
The rate constant k represents the continuous growth rate in the exponential model. It can be found by converting a given percentage growth rate to a decimal and using the relationship k = ln(1 + r), where r is the growth rate per time unit. Determining k allows accurate formulation of the growth function.
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Applying the Exponential Model to Population Prediction
To predict future population, substitute the initial population, the rate constant k, and the elapsed time into the exponential growth formula. This calculation estimates the population at a future date, assuming the growth rate remains constant, which is crucial for planning and analysis.
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