Assume that functions f and g are differentiable with f(1) = 2, f'(1) = −3, g(1) = 4, and g'(1) = −2. Find the equation of the line tangent to the graph of F(x) = f(x)g(x) at x = 1.
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
3. Techniques of Differentiation
Product and Quotient Rules
Problem 8.8.66b
Textbook Question
66–71. {Use of Tech} Estimating error Refer to Theorem 8.1 in the following exercises.
66. Let f(x) = cos(x²).
b. Calculate f''(x).
Verified step by step guidance1
Recall that the function is given by \(f(x) = \cos(x^2)\). Our goal is to find the second derivative \(f''(x)\).
First, find the first derivative \(f'(x)\) by applying the chain rule. The derivative of \(\cos(u)\) with respect to \(u\) is \(-\sin(u)\), and here \(u = x^2\). So, \(f'(x) = -\sin(x^2) \cdot \frac{d}{dx}(x^2)\).
Calculate the derivative of the inner function: \(\frac{d}{dx}(x^2) = 2x\). Substitute this back to get \(f'(x) = -2x \sin(x^2)\).
Next, find the second derivative \(f''(x)\) by differentiating \(f'(x) = -2x \sin(x^2)\). Use the product rule: if \(h(x) = u(x)v(x)\), then \(h'(x) = u'(x)v(x) + u(x)v'(x)\).
Let \(u(x) = -2x\) and \(v(x) = \sin(x^2)\). Then, \(u'(x) = -2\) and \(v'(x)\) requires the chain rule again: \(v'(x) = \cos(x^2) \cdot 2x\). Substitute these into the product rule formula to express \(f''(x)\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Second Derivative
The second derivative of a function measures the rate of change of the first derivative, providing information about the function's concavity and acceleration. It is found by differentiating the first derivative once more with respect to the variable.
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The Second Derivative Test: Finding Local Extrema
Chain Rule
The chain rule is a differentiation technique used when dealing with composite functions. It states that the derivative of f(g(x)) is f'(g(x)) multiplied by g'(x), allowing us to differentiate functions like cos(x²) effectively.
Recommended video:
Intro to the Chain Rule
Derivative of Trigonometric Functions
Understanding the derivatives of basic trigonometric functions, such as d/dx[cos(x)] = -sin(x), is essential. This knowledge helps in differentiating more complex functions involving trigonometric expressions.
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Derivatives of Other Inverse Trigonometric Functions
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