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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 10, Problem 10.4.47c

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.


c. Suppose f is a continuous, positive, decreasing function, for x ≥ 1, and aₖ = f(k), for k = 1, 2, 3, …. If ∑ (k = 1 to ∞) aₖ converges to L, then ∫ (1 to ∞) f(x) dx converges to L.

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Step 1: Understand the problem statement. We have a function \(f\) that is continuous, positive, and decreasing for \(x \geq 1\), and a sequence \(a_k = f(k)\) for \(k = 1, 2, 3, \ldots\). The series \(\sum_{k=1}^\infty a_k\) converges to some limit \(L\). We need to determine if the improper integral \(\int_1^\infty f(x) \, dx\) also converges to the same limit \(L\).
Step 2: Recall the Integral Test for convergence of series. The Integral Test states that if \(f\) is continuous, positive, and decreasing on \([1, \infty)\), then the series \(\sum_{k=1}^\infty f(k)\) and the integral \(\int_1^\infty f(x) \, dx\) either both converge or both diverge. However, this test does not say that their sums or values are equal, only that their convergence behavior matches.
Step 3: Analyze the relationship between the sum and the integral. The sum \(S = \sum_{k=1}^\infty f(k)\) is a discrete sum of function values at integers, while the integral \(I = \int_1^\infty f(x) \, dx\) is the continuous area under the curve. Although both converge or diverge together, their exact values are generally not equal.
Step 4: Consider a counterexample to show the values are not necessarily equal. For example, take \(f(x) = \frac{1}{x^2}\). The series \(\sum_{k=1}^\infty \frac{1}{k^2}\) converges to \(\frac{\pi^2}{6}\), while the integral \(\int_1^\infty \frac{1}{x^2} \, dx\) converges to 1. Since \(\frac{\pi^2}{6} \neq 1\), the integral and series limits are not equal.
Step 5: Conclusion: The statement is false because although the series and integral both converge, the integral does not necessarily converge to the same limit \(L\) as the series. The Integral Test guarantees convergence behavior but not equality of sums and integrals.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Comparison between Series and Improper Integrals

This concept explores the relationship between infinite series and improper integrals, especially when terms of the series come from evaluating a function at integers. While both can converge or diverge, their exact values and convergence behavior may differ, requiring careful analysis to determine equivalence.
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Improper Integrals: Infinite Intervals

Integral Test for Convergence

The integral test links the convergence of a series with positive, decreasing terms to the convergence of an improper integral of the corresponding function. It states that if the integral converges, so does the series, and vice versa, but it does not guarantee that their sums or values are equal.
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Choosing a Convergence Test

Counterexamples in Convergence Analysis

Counterexamples demonstrate that even when conditions like positivity, continuity, and monotonicity hold, the sum of a series and the value of the corresponding improper integral may not be equal. Such examples help clarify the limits of theorems and prevent incorrect assumptions about equality of limits.
Recommended video:
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Choosing a Convergence Test
Related Practice
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Textbook Question

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.


c. A series that converges conditionally must converge.

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Textbook Question

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{1, 2, 4, 8, 16, ......}

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Textbook Question

87. Explain why or why not

Determine whether the following statements are true and give an explanation or counterexample.


c. If ∑ aₖ converges, then ∑ (aₖ + 0.0001) converges.

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