Classify each of the following equations.
$2.5x+3.1=1.2(x-2)$

• A. Conditional
• B. Identity
• C. Contradiction

Answer: (A)

Verified step by step guidance

1. Start by writing down the given equation: \(2.5x + 3.1 = 1.2\left(x - 2\right)\).
2. Distribute the \$1.2\( on the right side to both terms inside the parentheses: \(1.2 \times x\) and \(1.2 \times (-2)\), resulting in \)1.2x - 2.4$.
3. Rewrite the equation with the distributed terms: \$2.5x + 3.1 = 1.2x - 2.4$.
4. Bring all terms involving \(x\) to one side and constants to the other side by subtracting \$1.2x\( from both sides and subtracting \)3.1\( from both sides: \)2.5x - 1.2x = -2.4 - 3.1$.
5. Simplify both sides to get a linear equation in the form \(ax = b\). Then analyze the result: if \(a \neq 0\), the equation is conditional (true for some \(x\)); if \(a = 0\) and \(b = 0\), it is an identity (true for all \(x\)); if \(a = 0\) and \(b \neq 0\), it is a contradiction (no solution).