Variations on the substitution method Evaluate the following integrals. ∫ (𝒵 + 1) √(3𝒵 + 2) d𝒵
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Identify the integral to solve: \(\int (Z + 1) \sqrt{3Z + 2} \, dZ\).
Choose a substitution to simplify the integral. Let \(u = 3Z + 2\), so that the expression under the square root becomes \(\sqrt{u}\).
Compute the differential \(du\) in terms of \(dZ\): since \(u = 3Z + 2\), then \(\frac{du}{dZ} = 3\), which implies \(dZ = \frac{du}{3}\).
Express \(Z\) in terms of \(u\) to rewrite the factor \((Z + 1)\): from \(u = 3Z + 2\), solve for \(Z\) to get \(Z = \frac{u - 2}{3}\), so \(Z + 1 = \frac{u - 2}{3} + 1 = \frac{u + 1}{3}\).
Rewrite the integral entirely in terms of \(u\) and \(du\): substitute \((Z + 1)\) and \(\sqrt{3Z + 2}\) with their expressions in \(u\), and replace \(dZ\) with \(\frac{du}{3}\). Then simplify the integrand before integrating with respect to \(u\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Substitution Method in Integration
The substitution method simplifies integrals by changing variables to transform a complicated integral into a basic form. It involves choosing a substitution u = g(z) such that the integral becomes easier to evaluate. This method is especially useful when the integral contains a composite function and its derivative.
The chain rule in differentiation helps identify the inner function and its derivative, which guides the substitution choice in integration. Recognizing the derivative of the inner function within the integral allows for an effective substitution, turning the integral into a simpler polynomial or standard form.
Integrals involving polynomials and roots often require rewriting the root as a fractional exponent. After substitution, the integral can be expressed as a sum of powers of the variable, which can be integrated using the power rule. Understanding how to manipulate and integrate these expressions is essential for solving such integrals.