1. Equations & Inequalities

Linear Equations

Textbook Question
Solve and check: 24 + 3 (x + 2) = 5(x − 12).
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Textbook Question
Solve each formula for the specified variable. Assume that the denominator is not 0 if variables appear in the denominator. s = 1/2gt², for g (distance traveled by a falling object)
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Textbook Question
Exercises 41–60 contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. b. Keeping the restrictions in mind, solve the equation. 5/2x - 8/9 = 1/18 - 1/3x
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Textbook Question
Exercises 41–60 contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. b. Keeping the restrictions in mind, solve the equation. (x - 2)/2x + 1 = (x + 1)/x
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Textbook Question
Exercises 41–60 contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. b. Keeping the restrictions in mind, solve the equation. 1/(x - 1) + 5 = 11/(x - 1)
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Textbook Question
Solve each equation for x. 2(x-a) +b =3x+a
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Textbook Question
Exercises 41–60 contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. b. Keeping the restrictions in mind, solve the equation. 3/(x + 4) - 7 = - 4/(x + 4)
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Textbook Question
Solve each equation for x. ax+b=3(x-a)
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Textbook Question
Solve each equation for x. x/a-1 = ax+3
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Textbook Question
Exercises 41–60 contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. b. Keeping the restrictions in mind, solve the equation. 3/(2x - 2) + 1/2 = 2/(x - 1)
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Textbook Question
Solve each equation for x. a²x + 3x =2a²
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Textbook Question
Exercises 41–60 contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. b. Keeping the restrictions in mind, solve the equation. 3/(x + 2) + 2/(x - 2) = 8/(x + 2)(x - 2)
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Textbook Question
Solve: 2x(x+3)+6(x−3)=−28. (Section 5.7, Example 2)
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Textbook Question
Find all values of x satisfying the given conditions. y₁ = 5(2x - 8) - 2, y₂ = 5(x - 3) + 3, and y₁ = y₂.
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Textbook Question
In Exercises 61–66, find all values of x satisfying the given conditions. $y_1 = \frac{x - 3}{5}, \quad y_2 = \frac{x - 5}{4}, \quad \text{and} \quad y_1 - y_2 = 1$
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