Solve each equation. 0.5x+ (4/3)x= x+10
1. Equations & Inequalities
Linear Equations
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Exercises 27–40 contain linear equations with constants in denominators. Solve each equation. x/3 = x/2 - 2
792views - Textbook QuestionIn Exercises 25-38, solve each equation.20 - x/3=x/2689views
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Solve each equation. 0.08x+0.06(x+12) = 7.72
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Exercises 27–40 contain linear equations with constants in denominators. Solve each equation. 20 - x/3 = x/2
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Exercises 27–40 contain linear equations with constants in denominators. Solve each equation. x/5 - 1/2 = x/6
841views1rank - Textbook QuestionIn Exercises 1–34, solve each rational equation. If an equation has no solution, so state.2/(x+3) − 5/(x+1) = (3x+5)/(x²+4x+3)774views
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Exercises 27–40 contain linear equations with constants in denominators. Solve each equation. 3x/5 = 2x/3 + 1
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Determine whether each equation is an identity, a conditional equation, or a contradiction. Give the solution set. (1/2)(6x+20) = x+4 +2(x+3)
1948views - Textbook QuestionIn Exercises 1–34, solve each rational equation. If an equation has no solution, so state.3y/(y²+5y+6) + 2/(y²+y−2) = 5y/(y²+2y−3)714views
- Textbook QuestionIn Exercises 25-38, solve each equation.(x + 3)/6 = 2/3 + (x - 5)/4680views
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Determine whether each equation is an identity, a conditional equation, or a contradiction. Give the solution set. 2(x-8) = 3x-16
1526views1comments - Textbook QuestionIn Exercises 25-38, solve each equation.x/4 =2 +(x-3)/3700views
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Exercises 27–40 contain linear equations with constants in denominators. Solve each equation. (x + 3)/6 = 3/8 + (x - 5)/4
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Exercises 27–40 contain linear equations with constants in denominators. Solve each equation. 5 + (x - 2)/3 = (x + 3)/8
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