Solve each equation in Exercises 41–60 by making an appropriate substitution. x(-2) - x(-1) - 6 = 0
1. Equations & Inequalities
Choosing a Method to Solve Quadratics
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- Textbook Question
Solve each equation in Exercises 41–60 by making an appropriate substitution. x - 13√x + 40 = 0
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Solve each equation in Exercises 96–102 by the method of your choice. 2√(x-1) = x
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Solve each radical equation in Exercises 11–30. Check all proposed solutions.
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Solve each radical equation in Exercises 11–30. Check all proposed solutions. √(6x + 1) = x - 1
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Solve each radical equation in Exercises 11–30. Check all proposed solutions. √(x + 3) = x - 3
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Solve each radical equation in Exercises 88–89. √ (2x-3) + x = 3
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Use the method described in Exercises 83–86, if applicable, and properties of absolute value to solve each equation or inequality. (Hint: Exercises 99 and 100 can be solved by inspection.) | x2 + 5x + 5 | = 1
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Use the method described in Exercises 83–86, if applicable, and properties of absolute value to solve each equation or inequality. (Hint: Exercises 99 and 100 can be solved by inspection.) | x2 - 9 | = x + 3
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Use the method described in Exercises 83–86, if applicable, and properties of absolute value to solve each equation or inequality. (Hint: Exercises 99 and 100 can be solved by inspection.) | 4x2 - 23x - 6 | = 0
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Match each equation in Column I with the correct first step for solving it in Column II. (x+5)2/3 - (x+5)1/3 - 6 = 0
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Solve each equation. x - √(2x+3) = 0
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Solve each equation. √(3x+7) = 3x+5
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Solve each equation. √(4x+13) = 2x-1
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Solve each equation. (√x+2)-x = 2
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