Find all values of x satisfying the given conditions. y1 = 2x2 + 5x - 4, y2 = - x2 + 15x - 10, and y1 - y2 = 0
1. Equations & Inequalities
Choosing a Method to Solve Quadratics
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Write a quadratic equation in general form whose solution set is {- 3, 5}.
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Solve each equation in Exercises 41–60 by making an appropriate substitution.
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Solve each equation in Exercises 41–60 by making an appropriate substitution. (x - 5)2 - 4(x - 5) - 21 = 0
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Solve each equation in Exercises 41–60 by making an appropriate substitution.
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Solve each equation with rational exponents in Exercises 31–40. Check all proposed solutions.
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Solve each equation in Exercises 41–60 by making an appropriate substitution. x(-2) - x(-1) - 6 = 0
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Solve each equation in Exercises 41–60 by making an appropriate substitution. x - 13√x + 40 = 0
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Solve each equation in Exercises 96–102 by the method of your choice. 2√(x-1) = x
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Solve each radical equation in Exercises 11–30. Check all proposed solutions.
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Solve each radical equation in Exercises 11–30. Check all proposed solutions. √(6x + 1) = x - 1
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Solve each radical equation in Exercises 11–30. Check all proposed solutions. √(x + 3) = x - 3
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Solve each radical equation in Exercises 88–89. √ (2x-3) + x = 3
246views - Textbook QuestionUse the method described in Exercises 83–86, if applicable, and properties ofabsolute value to solve each equation or inequality. (Hint: Exercises 99 and 100 canbe solved by inspection.) | x^2 + 5x + 5 | = 1393views
- Textbook QuestionUse the method described in Exercises 83–86, if applicable, and properties ofabsolute value to solve each equation or inequality. (Hint: Exercises 99 and 100 canbe solved by inspection.) | x^2 - 9 | = x + 3389views