Patricia has meters of fencing to make a rectangular garden in her backyard. She wants the length to be meters more than the width. Complete steps & of the word problem solving process to set up an equation Patricia could use to find the width of her rectangular fence.
Table of contents
- 1. Review of Real Numbers1h 28m
- 2. Linear Equations and Inequalities3h 38m
- 3. Solving Word Problems2h 36m
- 4. Graphing Linear Equations in Two Variables1h 50m
- 5. Systems of Linear Equations1h 25m
- 6. Exponents and Polynomials1h 27m
- 7. Factoring1h 30m
- 8. Rational Expressions and Equations2h 18m
- 9. Inequalities and Absolute Value2h 0m
- 10. Relations and Functions1h 10m
- 11. Roots, Radicals, and Complex Numbers2h 33m
- 12. Quadratic Equations and Functions1h 23m
- 13. Inverse, Exponential, & Logarithmic Functions1h 5m
- 14. Conic Sections & Systems of Nonlinear Equations58m
- 15. Sequences, Series, and the Binomial Theorem1h 20m
3. Solving Word Problems
Introduction to Problem Solving
Struggling with Beginning & Intermediate Algebra?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Find the unknown numbers.
One number is nine less than another. Their sum is negative twenty-seven.
A
−18 and −27
B
−18 and −9
C
−27 and −9
D
−9 and 18
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Verified step by step guidance1
Let the two unknown numbers be represented as variables. For example, let the first number be \(x\) and the second number be \(y\).
Translate the first statement "One number is nine less than another" into an equation. This can be written as \(x = y - 9\) or \(y = x + 9\) depending on which number you choose to express in terms of the other.
Translate the second statement "Their sum is negative twenty-seven" into an equation: \(x + y = -27\).
Substitute the expression from step 2 (for example, \(x = y - 9\)) into the sum equation from step 3 to get an equation with one variable: \((y - 9) + y = -27\).
Simplify the equation from step 4 and solve for the variable \(y\). Once you find \(y\), substitute it back into the expression from step 2 to find \(x\).
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