Suppose ABC is a right triangle with sides of lengths a, b, and c and right angle at C. Use the Pythagorean theorem to find the unknown side length. Then find exact values of the six trigonometric functions for angle B. Rationalize denominators when applicable. See Example 1. b = 8, c = 11
Table of contents
- 0. Review of College Algebra4h 45m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
3. Unit Circle
Defining the Unit Circle
Problem 31
Textbook Question
Find one solution for each equation. Assume all angles involved are acute angles. See Example 3. tan α = cot(α + 10°)
Verified step by step guidance1
Recall the definition of cotangent in terms of tangent: \(\cot \theta = \frac{1}{\tan \theta}\). So, rewrite the equation \(\tan \alpha = \cot(\alpha + 10^\circ)\) as \(\tan \alpha = \frac{1}{\tan(\alpha + 10^\circ)}\).
Multiply both sides of the equation by \(\tan(\alpha + 10^\circ)\) to eliminate the fraction: \(\tan \alpha \cdot \tan(\alpha + 10^\circ) = 1\).
Use the tangent addition formula to express \(\tan(\alpha + 10^\circ)\) in terms of \(\tan \alpha\) and \(\tan 10^\circ\): \(\tan(\alpha + 10^\circ) = \frac{\tan \alpha + \tan 10^\circ}{1 - \tan \alpha \tan 10^\circ}\).
Substitute this expression back into the equation from step 2: \(\tan \alpha \cdot \frac{\tan \alpha + \tan 10^\circ}{1 - \tan \alpha \tan 10^\circ} = 1\).
Multiply both sides by the denominator to clear the fraction and then rearrange the resulting equation to form a quadratic equation in terms of \(\tan \alpha\). Solve this quadratic equation to find possible values of \(\tan \alpha\), and then determine \(\alpha\) by taking the arctangent, considering that \(\alpha\) is an acute angle.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Relationship Between Tangent and Cotangent
Tangent and cotangent are reciprocal trigonometric functions, where tan(θ) = 1/cot(θ). Understanding that cotangent of an angle can be expressed as the tangent of its complement, cot(θ) = tan(90° - θ), helps in rewriting and solving equations involving both functions.
Recommended video:
Introduction to Cotangent Graph
Solving Trigonometric Equations
Solving trigonometric equations involves manipulating the equation using identities and algebraic techniques to isolate the variable. Recognizing equivalent expressions and applying inverse functions or angle relationships is essential to find valid angle solutions within given constraints.
Recommended video:
How to Solve Linear Trigonometric Equations
Acute Angle Constraints
When angles are restricted to acute angles (0° < angle < 90°), solutions must be checked to ensure they fall within this range. This constraint limits possible solutions and affects how inverse trigonometric functions are applied, ensuring the final answer is valid in the given context.
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Drawing Angles in Standard Position
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