Given two right triangles and , which congruency theorem can be used to prove that they are congruent? Choose from: , , , or .
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
2. Trigonometric Functions on Right Triangles
Trigonometric Functions on Right Triangles
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Which of the following expressions can be used to find the measure of angle in a right triangle if the lengths of the sides opposite and adjacent to are known?
A
B
C
D
Verified step by step guidance1
Recall the definitions of the primary trigonometric ratios in a right triangle relative to angle \(B\): sine is \(\sin B = \frac{\text{opposite}}{\text{hypotenuse}}\), cosine is \(\cos B = \frac{\text{adjacent}}{\text{hypotenuse}}\), and tangent is \(\tan B = \frac{\text{opposite}}{\text{adjacent}}\).
Since the problem states that the lengths of the sides opposite and adjacent to angle \(B\) are known, focus on the tangent ratio, which directly relates these two sides.
To find the measure of angle \(B\) using the tangent ratio, use the inverse tangent function (arctangent), which gives \(B = \arctan\left(\frac{\text{opposite}}{\text{adjacent}}\right)\).
Check the other options: \(B = \arctan\left(\frac{\text{adjacent}}{\text{opposite}}\right)\) reverses the ratio and is incorrect; \(B = \arcsin\left(\frac{\text{opposite}}{\text{hypotenuse}}\right)\) and \(B = \arccos\left(\frac{\text{adjacent}}{\text{hypotenuse}}\right)\) require the hypotenuse length, which is not given.
Therefore, the correct expression to find angle \(B\) when only the opposite and adjacent sides are known is \(B = \arctan\left(\frac{\text{opposite}}{\text{adjacent}}\right)\).
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