If and are diameters of circle that intersect at the center, what is the measure of angle ?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
1. Measuring Angles
Angles in Standard Position
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Given that angle is in standard position and its terminal side passes through the point on the unit circle, what is the measure of angle in degrees?
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Verified step by step guidance1
Recognize that the point (0, 1) lies on the unit circle, which means its coordinates satisfy the equation \(x^2 + y^2 = 1\).
Recall that an angle in standard position has its vertex at the origin and its initial side along the positive x-axis, with the terminal side passing through the given point.
Identify the coordinates (0, 1) correspond to the point on the unit circle where the x-coordinate is 0 and the y-coordinate is 1, which is directly above the origin on the y-axis.
Understand that the angle whose terminal side passes through (0, 1) is the angle that points straight up from the positive x-axis, which corresponds to \$90^\circ$.
Conclude that the measure of angle \(dcu\) in degrees is \$90^\circ$ because this is the angle formed by the terminal side passing through (0, 1) on the unit circle.
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