Given a right triangle where the length of one leg is and the length of the other leg is , what is the length of the hypotenuse ?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
2. Trigonometric Functions on Right Triangles
Solving Right Triangles
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Given a right triangle where one leg has length units and the other leg has length units, what is the length of the hypotenuse? Round your answer to the nearest hundredth.
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Verified step by step guidance1
Identify the given information: the two legs of the right triangle have lengths 5 units and 12 units.
Recall the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse length \(c\) is equal to the sum of the squares of the legs: \(c^2 = a^2 + b^2\).
Substitute the given leg lengths into the formula: \(c^2 = 5^2 + 12^2\).
Calculate the squares of the legs: \$5^2 = 25\( and \)12^2 = 144\(, then add them to get \)c^2 = 25 + 144$.
Take the square root of both sides to solve for \(c\): \(c = \sqrt{25 + 144}\), which gives the length of the hypotenuse.
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