Given triangle with sides , , and opposite angles , , and respectively, which equation can be used to find the measure of angle using the Law of Sines?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
7. Non-Right Triangles
Law of Sines
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Which of the following statements correctly describes the requirement for two triangles to be proven similar by the (Side-Angle-Side) similarity theorem?
A
All three pairs of corresponding angles are equal.
B
All three pairs of corresponding sides are in proportion.
C
Two pairs of corresponding angles are equal and one pair of sides are in proportion.
D
Two pairs of corresponding sides are in proportion and the included angles are equal.
Verified step by step guidance1
Recall that the SAS (Side-Angle-Side) similarity theorem states that two triangles are similar if two pairs of corresponding sides are in proportion and the included angle between those sides is equal.
Identify the key components of the SAS similarity condition: it requires two sides and the angle between them, not just any sides or angles.
Understand that 'included angle' means the angle formed between the two sides being compared, which is crucial for the SAS similarity to hold.
Compare the given options to the SAS similarity criteria: the correct statement must mention two pairs of sides in proportion and the included angle equal.
Conclude that the correct description is: 'Two pairs of corresponding sides are in proportion and the included angles are equal,' as this matches the SAS similarity theorem exactly.
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