Given the polar equation , which of the following best describes the shape of its graph on the unit circle?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
3. Unit Circle
Trigonometric Functions on the Unit Circle
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Find the sine, cosine, and tangent of each angle using the unit circle.
θ=225°,(−22,−22) 
A
sinθ=−22,cosθ=−22,tanθ=2
B
sinθ=22,cosθ=−22,tanθ=−1
C
sinθ=−22,cosθ=−22,tanθ=1
D
sinθ=22,cosθ=22,tanθ=12
Verified step by step guidance1
The unit circle is a circle with a radius of 1 centered at the origin of a coordinate plane. Each point on the unit circle corresponds to an angle θ measured from the positive x-axis.
For an angle θ = 225°, locate the point on the unit circle. The coordinates of this point are given as (-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}).
The x-coordinate of the point on the unit circle represents the cosine of the angle, and the y-coordinate represents the sine of the angle. Therefore, \cos(225°) = -\frac{\sqrt{2}}{2} and \sin(225°) = -\frac{\sqrt{2}}{2}.
The tangent of an angle θ is the ratio of the sine to the cosine, \tan(θ) = \frac{\sin(θ)}{\cos(θ)}. For θ = 225°, \tan(225°) = \frac{-\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} = 1.
Verify the quadrant: 225° is in the third quadrant where both sine and cosine are negative, confirming that \sin(225°) = -\frac{\sqrt{2}}{2}, \cos(225°) = -\frac{\sqrt{2}}{2}, and \tan(225°) = 1 are correct.
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