A pilot is flying at 168 mph. She wants her flight path to be on a bearing of 57° 40′. A wind is blowing from the south at 27.1 mph. Find the bearing she should fly, and find the plane's ground speed.
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
8. Vectors
Geometric Vectors
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Given that segment is units long, what is the length of if and are collinear and is a part of where is units long?
A
units
B
units
C
units
D
units
Verified step by step guidance1
Identify the given segments and their relationships: segment \( TQ \) is 26 units long, and segment \( TV \) is 32 units long, with \( TQ \) being part of \( TV \).
Since \( TQ \) and \( QV \) are collinear and \( TQ \) is part of \( TV \), the length of \( TV \) is the sum of the lengths of \( TQ \) and \( QV \). This can be expressed as: \( TV = TQ + QV \).
Substitute the known values into the equation: \( 32 = 26 + QV \).
To find the length of \( QV \), isolate \( QV \) by subtracting \( 26 \) from both sides: \( QV = 32 - 26 \).
Simplify the expression to find the length of \( QV \).
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