If the vertex angle of an isosceles triangle is , what is the measure of each base angle?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
2. Trigonometric Functions on Right Triangles
Solving Right Triangles
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Given two right cones, one with a base radius of units and height units, and another with a base radius of units and height units, which value of would make the two cones similar?
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B
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Verified step by step guidance1
Recall that two cones are similar if their corresponding linear dimensions are proportional. This means the ratio of their base radii must be equal to the ratio of their heights.
Set up the proportion using the given radii and heights: \(\frac{4}{8} = \frac{x}{12}\), where 4 and 8 are the base radii of the smaller and larger cones respectively, and \(x\) and 12 are their heights.
Simplify the ratio of the radii: \(\frac{4}{8} = \frac{1}{2}\), so the proportion becomes \(\frac{1}{2} = \frac{x}{12}\).
Solve for \(x\) by cross-multiplying: \$1 \times 12 = 2 \times x\(, which simplifies to \)12 = 2x$.
Divide both sides by 2 to isolate \(x\): \(x = \frac{12}{2}\), which gives the value of \(x\) that makes the two cones similar.
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