A force of 30.0 lb is required to hold an 80.0-lb pressure washer on an incline. What angle does the incline make with the horizontal?
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1
Identify the forces acting on the pressure washer: the gravitational force (weight) and the force required to hold it on the incline.
Recognize that the force required to hold the pressure washer is the component of the gravitational force parallel to the incline.
Use the formula for the parallel component of the gravitational force: \( F_{\text{parallel}} = W \cdot \sin(\theta) \), where \( W \) is the weight of the pressure washer and \( \theta \) is the angle of the incline.
Set up the equation using the given values: \( 30.0 = 80.0 \cdot \sin(\theta) \).
Solve for \( \theta \) by isolating \( \sin(\theta) \) and then using the inverse sine function: \( \theta = \sin^{-1}\left(\frac{30.0}{80.0}\right) \).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Forces on an Incline
When an object is on an incline, the forces acting on it can be resolved into components parallel and perpendicular to the surface. The weight of the object can be split into these components, where the parallel component causes the object to slide down the incline, and the perpendicular component is countered by the normal force.
Trigonometric functions, particularly sine and cosine, are essential for relating angles to the ratios of the sides of a right triangle. In the context of an incline, the sine of the angle can be used to find the ratio of the opposite side (force parallel to the incline) to the hypotenuse (weight of the object), while the cosine relates to the adjacent side (normal force).
In this scenario, the pressure washer is in equilibrium, meaning the forces acting on it are balanced. The force required to hold the washer in place (30.0 lb) equals the component of the weight acting down the incline. By applying the equilibrium condition, one can set up an equation to solve for the angle of the incline using the known forces.