Match each function in Column I with the appropriate description in Column II.
I y = 3 sin(2x - 4)
II A. amplitude = 2, period = π/2, phase shift = ¾ B. amplitude = 3, period = π, phase shift = 2 C. amplitude = 4, period = 2π/3, phase shift = ⅔ D. amplitude = 2, period = 2π/3, phase shift = 4⁄3
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Identify the general form of the sine function: \(y = A \sin(Bx - C)\), where \(A\) is the amplitude, \(B\) affects the period, and \(C\) affects the phase shift.
From the given function \(y = 3 \sin(2x - 4)\), note that the amplitude \(A\) is the coefficient before the sine, which is 3.
Calculate the period using the formula \(\text{Period} = \frac{2\pi}{B}\). Here, \(B = 2\), so the period is \(\frac{2\pi}{2} = \pi\).
Find the phase shift using the formula \(\text{Phase shift} = \frac{C}{B}\). Since the function is \(\sin(2x - 4)\), rewrite the inside as \$2(x - 2)$, so the phase shift is \(\frac{4}{2} = 2\).
Match the values amplitude = 3, period = \(\pi\), and phase shift = 2 with the correct description in Column II, which corresponds to option B.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Amplitude of a Sine Function
Amplitude is the maximum value or height of the sine wave from its midline. For a function y = a sin(bx + c), the amplitude is the absolute value of 'a'. It determines how far the graph stretches vertically from the center line.
The period is the length of one complete cycle of the sine wave. It is calculated as (2π) divided by the absolute value of the coefficient 'b' in y = a sin(bx + c). The period tells how frequently the wave repeats over the x-axis.
Phase shift is the horizontal translation of the sine graph, determined by solving (bx + c) = 0 for x. It equals -c/b and indicates how far the graph shifts left or right from the origin. This shift affects where the wave starts on the x-axis.