Solve each equation for exact solutions. 6 sin⁻¹ x = 5π
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Start with the given equation: \(6 \sin^{-1} x = 5\pi\).
Isolate the inverse sine function by dividing both sides of the equation by 6: \(\sin^{-1} x = \frac{5\pi}{6}\).
Recall that \(\sin^{-1} x\) (also called arcsin) gives the angle whose sine is \(x\), and its principal value range is \([-\frac{\pi}{2}, \frac{\pi}{2}]\).
Check if \(\frac{5\pi}{6}\) lies within the principal range of \(\sin^{-1} x\). Since \(\frac{5\pi}{6}\) is greater than \(\frac{\pi}{2}\), it is outside the principal range, so consider the periodicity and properties of sine to find all possible solutions.
Use the sine function to write \(x = \sin\left( \frac{5\pi}{6} \right)\) and then find all \(x\) values that satisfy this equation within the domain of \(\sin^{-1} x\), considering the sine function's symmetry and periodicity.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Inverse Sine Function (sin⁻¹ or arcsin)
The inverse sine function, sin⁻¹(x), returns the angle whose sine is x. Its output range is limited to [-π/2, π/2], meaning it only gives principal values within this interval. Understanding this range is crucial when solving equations involving sin⁻¹.
Solving trigonometric equations involves isolating the trigonometric function and then finding all possible angles that satisfy the equation within the given domain. For inverse functions, solutions must respect the function's principal range or be adjusted accordingly.
Exact solutions in trigonometry are expressed in terms of π or known special angles rather than decimal approximations. Radian measure is the standard unit for angles in higher mathematics, where π radians equal 180 degrees, facilitating precise and exact answers.