Given the vertices of a triangle at , , and , use the Law of Cosines to find, correct to the nearest degree, the three angles of the triangle.
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
7. Non-Right Triangles
Law of Cosines
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Solve the triangle: b=5,c=3,A=100°.
A
a=6.05,B=50.4°,C=29.6°
B
a=6.26,B=28.2°,C=51.8°
C
a=6.26,B=51.8°,C=28.2°
D
a=6.05,B=29.6°,C=50.4°
Verified step by step guidance1
Identify the given values: side b = 5, side c = 3, and angle A = 100°.
Use the Law of Cosines to find side a. The formula is: a^2 = b^2 + c^2 - 2bc * cos(A). Substitute the known values into the formula.
Calculate the value of a using the substituted values in the Law of Cosines equation.
Use the Law of Sines to find angle B. The formula is: sin(B)/b = sin(A)/a. Substitute the known values and solve for angle B.
Calculate angle C using the fact that the sum of angles in a triangle is 180°. Use the equation: C = 180° - A - B.
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