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Ch. 10 - Eukaryotic Chromosome Abnormalities and Molecular Organization
Sanders - Genetic Analysis: An Integrated Approach 3rd Edition
Sanders3rd EditionGenetic Analysis: An Integrated ApproachISBN: 9780135564172Not the one you use?Change textbook
Chapter 10, Problem 31c

For the following crosses, determine as accurately as possible the genotypes of each parent, the parent in whom nondisjunction occurs, and whether nondisjunction takes place in the first or second meiotic division. Both color blindness and hemophilia, a blood-clotting disorder, are X-linked recessive traits. In each case, assume the parents have normal karyotypes.
A color-blind man and a woman who is wild type have a daughter with Turner syndrome (XO) who has normal color vision and blood clotting.

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1
Step 1: Understand the genetic basis of the traits and the chromosomal abnormality. Color blindness and hemophilia are X-linked recessive traits, meaning they are carried on the X chromosome. Turner syndrome (XO) results from a missing X chromosome, leading to a 45,X karyotype.
Step 2: Analyze the genotypes of the parents. The man is color-blind, so his genotype is XcY, where Xc represents the X chromosome carrying the color-blind allele. The woman is wild type, meaning she has two normal X chromosomes (X+X+).
Step 3: Determine the possible gametes produced by each parent. The man can produce gametes with either Xc or Y. The woman can produce gametes with X+.
Step 4: Consider the nondisjunction event. Since the daughter has Turner syndrome (XO) and normal color vision, she must have inherited one X chromosome from her mother (X+) and no sex chromosome from her father. This indicates nondisjunction occurred in the father during meiosis.
Step 5: Identify the stage of nondisjunction. If nondisjunction occurred in the first meiotic division, the father would produce gametes with both Xc and Y or no sex chromosome at all. If it occurred in the second meiotic division, the father would produce gametes with either Xc, Y, or no sex chromosome. Since the daughter inherited no sex chromosome from the father, nondisjunction likely occurred in the second meiotic division.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

X-linked Inheritance

X-linked inheritance refers to the pattern of inheritance for genes located on the X chromosome. In this case, color blindness and hemophilia are X-linked recessive traits, meaning that males (XY) are more likely to express these traits since they have only one X chromosome. Females (XX) can be carriers if they have one affected X chromosome but typically do not express the trait unless both X chromosomes are affected.
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X-Inactivation

Nondisjunction

Nondisjunction is the failure of homologous chromosomes or sister chromatids to separate properly during cell division, leading to gametes with an abnormal number of chromosomes. This can occur during either the first or second meiotic division. In the context of Turner syndrome (XO), nondisjunction likely occurred during the formation of the egg or sperm, resulting in a missing X chromosome in the daughter.
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Allopolyploidy

Turner Syndrome

Turner syndrome is a chromosomal disorder characterized by the presence of a single X chromosome (XO) in females, leading to various developmental and physical features. Individuals with Turner syndrome typically have normal intelligence but may experience short stature, infertility, and other health issues. In this scenario, the daughter with Turner syndrome has normal color vision and blood clotting, indicating that she inherited a normal X chromosome from her mother.
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Related Practice
Textbook Question

Human chromosome 5 and the corresponding chromosomes from chimpanzee, gorilla, and orangutan are shown here. Describe any structural differences you see in the other primate chromosomes in relation to the human chromosome.

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Textbook Question

For the following crosses, determine as accurately as possible the genotypes of each parent, the parent in whom nondisjunction occurs, and whether nondisjunction takes place in the first or second meiotic division. Both color blindness and hemophilia, a blood-clotting disorder, are X-linked recessive traits. In each case, assume the parents have normal karyotypes.

A man and a woman who each has the wild-type phenotype have a son with Klinefelter syndrome (XXY) who has hemophilia.

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views
Textbook Question

For the following crosses, determine as accurately as possible the genotypes of each parent, the parent in whom nondisjunction occurs, and whether nondisjunction takes place in the first or second meiotic division. Both color blindness and hemophilia, a blood-clotting disorder, are X-linked recessive traits. In each case, assume the parents have normal karyotypes.

A man who is color blind and a woman who is wild type have a son with Jacob syndrome (XYY) who has hemophilia.

529
views
Textbook Question

For the following crosses, determine as accurately as possible the genotypes of each parent, the parent in whom nondisjunction occurs, and whether nondisjunction takes place in the first or second meiotic division. Both color blindness and hemophilia, a blood-clotting disorder, are X-linked recessive traits. In each case, assume the parents have normal karyotypes.

A man who is color blind and has hemophilia and a woman who is wild type have a daughter with triple X syndrome (XXX) who has hemophilia and normal color vision.

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views
Textbook Question

A healthy couple with a history of three previous spontaneous abortions has just had a child with cri-du-chat syndrome, a disorder caused by a terminal deletion of chromosome 5. Their physician orders karyotype analysis of both parents and of the child. The karyotype results for chromosomes 5 and 12 are shown here. Are the chromosomes in the child consistent with those expected in a case of cri-du-chat syndrome? Explain your reasoning.

676
views
Textbook Question

A healthy couple with a history of three previous spontaneous abortions has just had a child with cri-du-chat syndrome, a disorder caused by a terminal deletion of chromosome 5. Their physician orders karyotype analysis of both parents and of the child. The karyotype results for chromosomes 5 and 12 are shown here. Which parent has an abnormal karyotype? How can you tell? What is the nature of the abnormality?

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views