Given two triangles where in the first triangle, = , = , and side = , and in the second triangle, = , = , and side = , are the triangles congruent? If so, why?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
7. Non-Right Triangles
Law of Sines
Struggling with Trigonometry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
In triangle , the length of side is centimeters. If angle is and angle is , what is the length of side ?
A
centimeters
B
centimeters
C
centimeters
D
centimeters
Verified step by step guidance1
Identify the given elements in triangle LNP: side LN = 28 cm, angle P = 30°, and angle N = 60°.
Calculate the remaining angle L using the triangle angle sum property: \(\angle L = 180^\circ - \angle N - \angle P\).
Use the Law of Sines, which states \(\frac{\text{side opposite to } \angle L}{\sin(\angle L)} = \frac{\text{side opposite to } \angle N}{\sin(\angle N)} = \frac{\text{side opposite to } \angle P}{\sin(\angle P)}\).
Set up the ratio using the known side LN (opposite angle P) and the side LP (opposite angle N): \(\frac{LN}{\sin(\angle P)} = \frac{LP}{\sin(\angle N)}\).
Rearrange the equation to solve for LP: \(LP = LN \times \frac{\sin(\angle N)}{\sin(\angle P)}\).
Watch next
Master Intro to Law of Sines with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Multiple Choice
14
views

