Find $f(-3)$ for the following functions.
(A) $f\left(x\right)=2x^2-4x+1$

• A. $31$
• B. $29$
• C. $34$
• D. $25$

Answer: (A)

Verified step by step guidance

1. Identify the function given: \(f(x) = 2x^2 - 4x + 1\).
2. Substitute the value \(x = -3\) into the function to find \(f(-3)\), so write \(f(-3) = 2(-3)^2 - 4(-3) + 1\).
3. Calculate the square of \(-3\), which is \((-3)^2 = 9\), and rewrite the expression as \(f(-3) = 2(9) - 4(-3) + 1\).
4. Multiply the constants: \$2 \times 9\( and \)-4 \times (-3)\(, so the expression becomes \)f(-3) = 18 + 12 + 1$.
5. Add all the terms together: \$18 + 12 + 1\( to get the value of \)f(-3)$.