Given the linear inequality , determine if the following ordered pair is a solution to the inequality.
$(\frac{2}{3},\frac{1}{8})$

• A. Yes
• B. No
• C. Cannot be determined

Answer: (B)

Verified step by step guidance

1. Start with the given inequality: \$4y < 3x - 2$.
2. Substitute the coordinates of the ordered pair \(\left(\frac{2}{3}, \frac{1}{8}\right)\) into the inequality, replacing \(x\) with \(\frac{2}{3}\) and \(y\) with \(\frac{1}{8}\).
3. Calculate the left side by multiplying \$4$ by \(\frac{1}{8}\), which gives \(4 \times \frac{1}{8}\).
4. Calculate the right side by multiplying \$3\( by \(\frac{2}{3}\) and then subtracting \)2$, which gives \(3 \times \frac{2}{3} - 2\).
5. Compare the two results to check if the inequality \$4y < 3x - 2$ holds true with the substituted values. If the left side is less than the right side, the ordered pair is a solution; otherwise, it is not.