In a standard normal distribution, approximately what percentage of the data falls within one standard deviation of the mean (that is, between and on the z-score scale)?
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
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- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
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- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
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- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
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- 11. Correlation1h 24m
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- 14. ANOVA1h 57m
6. Normal Distribution and Continuous Random Variables
Standard Normal Distribution
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
For the standard normal distribution, what is the area under the curve between and ?
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Verified step by step guidance1
Recall that the standard normal distribution is a normal distribution with mean \(\mu = 0\) and standard deviation \(\sigma = 1\). The area under the curve between two \(z\)-values represents the probability that a standard normal random variable falls between those values.
Identify the two \(z\)-values given: \(z = 0.0\) and \(z = 1.79\). We want to find the area under the standard normal curve between these two points.
Use the standard normal cumulative distribution function (CDF), denoted as \(\Phi(z)\), which gives the area under the curve to the left of a given \(z\)-value. Specifically, \(\Phi(z)\) is the probability that the variable is less than or equal to \(z\).
Calculate the area between \(z=0.0\) and \(z=1.79\) by subtracting the CDF value at \(z=0.0\) from the CDF value at \(z=1.79\):
\(\text{Area} = \Phi(1.79) - \Phi(0.0)\)
Look up the values of \(\Phi(1.79)\) and \(\Phi(0.0)\) in the standard normal table or use a calculator/software that provides the standard normal CDF. Since \(\Phi(0.0) = 0.5\), the area is \(\Phi(1.79) - 0.5\). This difference gives the probability between the two \(z\)-scores.
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