Given segment in the plane, what is the image of segment after a -degree clockwise rotation about point ?
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0. Review of College Algebra
Transformations
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In the coordinate plane, what is the rule for a rotation about the origin that maps a point to its image?
A
maps to
B
maps to
C
maps to
D
maps to
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Verified step by step guidance1
Recall that a rotation of 180\degree about the origin in the coordinate plane means turning every point around the origin by 180\degree in the counterclockwise direction.
Use the rotation formulas for a point \((x, y)\) rotated by an angle \(\theta\) about the origin:
\[\left(x', y'\right) = \left(x \cos \theta - y \sin \theta, x \sin \theta + y \cos \theta\right)\]
Substitute \(\theta = 180\degree\) into the formulas. Recall that \(\cos 180\degree = -1\) and \(\sin 180\degree = 0\), so the formulas become:
\[x' = x \times (-1) - y \times 0 = -x\]
\[y' = x \times 0 + y \times (-1) = -y\]
Therefore, the image of the point \((x, y)\) after a 180\degree rotation about the origin is \((-x, -y)\).
Compare this result with the given options to identify the correct mapping rule for the 180\degree rotation.
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