If point is equidistant from the sides of triangle , which of the following must be true?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
2. Trigonometric Functions on Right Triangles
Trigonometric Functions on Right Triangles
Multiple Choice
Given a right triangle where the side adjacent to angle is units and the hypotenuse is units, what is the value of ?
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Verified step by step guidance1
Identify the given elements in the right triangle: the side adjacent to angle \( \theta \) is 4 units, and the hypotenuse is 5 units.
Recall the definition of secant in terms of cosine: \( \sec(\theta) = \frac{1}{\cos(\theta)} \).
Express cosine of angle \( \theta \) using the adjacent side and hypotenuse: \( \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{4}{5} \).
Calculate secant by taking the reciprocal of cosine: \( \sec(\theta) = \frac{1}{\cos(\theta)} = \frac{1}{\frac{4}{5}} \).
Simplify the expression for secant: \( \sec(\theta) = \frac{5}{4} \).
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