Skip to main content
Ch. 4 - Graphs of the Circular Functions
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161Not the one you use?Change textbook
Chapter 5, Problem 37

For each function, give the amplitude, period, vertical translation, and phase shift, as applicable.
y = 2 - sin(3x - π/5)

Verified step by step guidance
1
Identify the general form of the sine function: \(y = A \sin(Bx - C) + D\), where \(A\) is the amplitude, \(\frac{2\pi}{B}\) is the period, \(D\) is the vertical translation, and the phase shift is given by \(\frac{C}{B}\).
Rewrite the given function \(y = 2 - \sin(3x - \frac{\pi}{5})\) to match the general form. Notice that \(2 - \sin(3x - \frac{\pi}{5})\) can be seen as \(y = -\sin(3x - \frac{\pi}{5}) + 2\).
Determine the amplitude \(A\) by taking the absolute value of the coefficient in front of the sine function. Here, the coefficient is \(-1\), so \(A = | -1 | = 1\).
Calculate the period using the formula \(\text{Period} = \frac{2\pi}{B}\), where \(B\) is the coefficient of \(x\) inside the sine function. Here, \(B = 3\), so the period is \(\frac{2\pi}{3}\).
Find the vertical translation \(D\), which is the constant added outside the sine function. Here, \(D = 2\). Then, find the phase shift by dividing \(C\) by \(B\): \(\text{Phase shift} = \frac{\frac{\pi}{5}}{3} = \frac{\pi}{15}\). Since the function is \(\sin(3x - \frac{\pi}{5})\), the phase shift is to the right by \(\frac{\pi}{15}\).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Amplitude of a Trigonometric Function

Amplitude measures the maximum distance a sine or cosine function's graph reaches from its midline. It is the absolute value of the coefficient before the sine or cosine term. For y = 2 - sin(3x - π/5), the amplitude is | -1 | = 1, since the sine coefficient is implicitly -1.
Recommended video:
6:04
Introduction to Trigonometric Functions

Period of a Sine Function

The period is the length of one complete cycle of the sine function. It is calculated as 2π divided by the absolute value of the coefficient of x inside the function. For y = 2 - sin(3x - π/5), the period is 2π/3, reflecting how the function compresses horizontally.
Recommended video:
5:33
Period of Sine and Cosine Functions

Vertical Translation and Phase Shift

Vertical translation shifts the graph up or down and is given by the constant added outside the sine function, here +2. Phase shift moves the graph horizontally and is found by solving the inside of the sine function for zero: 3x - π/5 = 0, so the phase shift is π/15 units to the right.
Recommended video:
6:31
Phase Shifts