Solve each quadratic equation using the square root property.
$3x^2+3=51$

• A. $x=\pm2$
• B. $x\pm3\sqrt2$
• C. $x=\pm16$
• D. $x=\pm4$

Answer: (D)

Verified step by step guidance

1. Start with the given quadratic equation: \$3x^2 + 3 = 51$.
2. Isolate the \(x^2\) term by subtracting 3 from both sides: \$3x^2 = 51 - 3$.
3. Simplify the right side: \$3x^2 = 48$.
4. Divide both sides by 3 to solve for \(x^2\): \(x^2 = \frac{48}{3}\).
5. Apply the square root property by taking the square root of both sides: \(x = \pm \sqrt{\frac{48}{3}}\).