Solve each quadratic equation using the square root property.
$2y^2=54$

• A. $y=\pm9$
• B. $y=\pm3\sqrt3$
• C. $y=27$
• D. $y=\pm\sqrt3$

Answer: (B)

Verified step by step guidance

1. Start with the given quadratic equation: \$2y^2 = 54$.
2. Isolate the \(y^2\) term by dividing both sides of the equation by 2: \(y^2 = \frac{54}{2}\).
3. Simplify the right side to get \(y^2 = 27\).
4. Apply the square root property, which states that if \(y^2 = k\), then \(y = \pm \sqrt{k}\). So, write \(y = \pm \sqrt{27}\).
5. Simplify the square root by factoring 27 into \$9 \times 3\(, then take the square root of 9 out of the radical: \)y = \pm 3\sqrt{3}$.