Add the following and simplify the sum if possible.
$\frac{x+1}{3x}+\frac{2x-1}{3x}$

• A. $1$
• B. $-1$
• C. $x$
• D. $-x$

Answer: (A)

Verified step by step guidance

1. Identify that both fractions have the same denominator, which is \$3x$. When adding fractions with the same denominator, you can add the numerators directly and keep the denominator the same.
2. Write the sum of the fractions as a single fraction: \(\frac{x+1}{3x} + \frac{2x-1}{3x} = \frac{(x+1) + (2x-1)}{3x}\).
3. Combine like terms in the numerator: add \(x\) and \$2x\(, and add \)1\( and \)-1$ separately to simplify the numerator.
4. After simplifying the numerator, write the fraction as \(\frac{\text{simplified numerator}}{3x}\).
5. Check if the numerator and denominator have any common factors that can be canceled to simplify the fraction further.