Use substitution to solve the following system of linear equations.
$4 x + y = 1$
$x - y = 4$

$$\left$(-1,3$\right$)$

$$\left$(-3,1$\right$)$

$$\left$(3,-1$\right$)$

$$\left$(1,-3$\right$)$

Verified step by step guidance

Start with the given system of equations: \$4x + y = 1$ and $x - y = 4$.

From the second equation, solve for $x$ in terms of $y$: $x = y + 4$.

Substitute the expression for $x$ from step 2 into the first equation: \$4(y + 4) + y = 1$.

Simplify and solve the resulting equation for $y$: \$4y + 16 + y = 1$ which simplifies to $5y + 16 = 1$.

Once you find $y$, substitute it back into $x = y + 4$ to find the value of $x$.

Master Solving Systems of Linear Equations - Substitution with a bite sized video explanation from Patrick Ford

Use substitution to solve the following system of linear equations.4x+y=14x+y=1 x−y=4x-y=4