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Ch. 8 - Hypothesis Testing with Two Samples
Larson - Elementary Statistics: Picturing the World 8th Edition
Larson8th EditionElementary Statistics: Picturing the WorldISBN: 9780137493470Not the one you use?Change textbook
Chapter 8, Problem 8.2.9

Test the claim about the difference between two population means and at the level of significance α. Assume the samples are random and independent, and the populations are normally distributed.
Claim: μ1=μ2, α=0.01, Assume (σ1)^2=(σ2)^2
Sample statistics:
x̅1=33.7, s1=3.5 , n1=12 and x̅2=35.5 , s2=2.2 , n2=17

Verified step by step guidance
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Step 1: Identify the null and alternative hypotheses. The null hypothesis (H₀) is that the population means are equal, μ₁ = μ₂. The alternative hypothesis (Hₐ) is that the population means are not equal, μ₁ ≠ μ₂. This is a two-tailed test.
Step 2: Determine the test statistic formula. Since the population variances are assumed to be equal (σ₁² = σ₂²), we use the pooled t-test formula. The test statistic is given by: t = (x̄₁ - x̄₂) / √(sp²(1/n₁ + 1/n₂)), where sp² is the pooled variance.
Step 3: Calculate the pooled variance (sp²). The formula for sp² is: sp² = [(n₁ - 1)s₁² + (n₂ - 1)s₂²] / (n₁ + n₂ - 2). Substitute the given values for n₁, n₂, s₁, and s₂ to compute sp².
Step 4: Compute the test statistic (t). Substitute the values of x̄₁, x̄₂, sp², n₁, and n₂ into the t-test formula to calculate the t-value.
Step 5: Compare the calculated t-value to the critical t-value. Use the t-distribution table with degrees of freedom df = n₁ + n₂ - 2 and significance level α = 0.01 (two-tailed) to find the critical t-value. If the absolute value of the calculated t is greater than the critical t-value, reject the null hypothesis; otherwise, fail to reject the null hypothesis.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hypothesis Testing

Hypothesis testing is a statistical method used to make decisions about population parameters based on sample data. It involves formulating a null hypothesis (H0) and an alternative hypothesis (H1), then using sample statistics to determine whether to reject H0 in favor of H1. In this case, the null hypothesis states that the means of the two populations are equal (μ1=μ2).
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Significance Level (α)

The significance level, denoted as α, is the probability of rejecting the null hypothesis when it is actually true, also known as a Type I error. In this scenario, α is set at 0.01, indicating a 1% risk of concluding that there is a difference between the population means when there is none. This level of significance helps determine the threshold for making statistical inferences.
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Pooled Variance

Pooled variance is used when comparing two sample means under the assumption that the populations have equal variances. It combines the variances of both samples to provide a more accurate estimate of the common variance. In this question, the assumption (σ1)^2=(σ2)^2 allows for the calculation of a pooled variance, which is essential for conducting the t-test for the difference between the two means.
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Related Practice
Textbook Question

Independent and Dependent Samples In Exercises 5–8, classify the two samples as independent or dependent and justify your answer.

Sample 1: The maximum bench press weights for 53 football players

Sample 2: The maximum bench press weights for the same 53 football players after completing a weight lifting program

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Textbook Question

Constructing Confidence Intervals for μd To construct a confidence interval for μd , use the inequality below.

Construct the indicated confidence interval for μd . Assume the populations are normally distributed.

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Textbook Question

Constructing Confidence Intervals for μ1-μ2. When the sampling distribution for x̅1-x̅2 is approximated by a t-distribution and the populations have equal variances, you can construct a confidence interval for μ1-μ2, as shown below.

Construct the indicated confidence interval for μ1-μ2 . Assume the populations are approximately normal with equal variances.

Family Doctor 

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Textbook Question

Testing the Difference Between Two Means In Exercises 15–24, (a) identify the claim and state Ho and Ha, (b) find the critical value(s) and identify the rejection region(s), (c) find the standardized test statistic z, (d) decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim. Assume the samples are random and independent, and the populations are normally distributed.

Bed-in-a-Box To compare customer satisfaction with mattresses that are delivered compressed in a box and traditional mattresses, a researcher randomly selects 30 ratings of mattresses in boxes and 30 ratings of traditional mattresses. The mean rating of mattresses in boxes is 68.7 out of 100. Assume the population standard deviation is 6.6. The mean rating of traditional mattresses is 70.9 out of 100. Assume the population standard deviation is 5.6. At α=0.01, can the researcher support the claim that the mean rating of traditional mattresses is greater than the mean rating of mattresses in a box? (Adapted from Consumer Reports)

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Textbook Question

Daily Activities In Exercises 19–22, the results of a survey of 200 U.S. randomly selected U.S. men and 300 randomly selected U.S. women are shown in the figure at the left, which displays the percentages engaged in working or socializing and communicating on an average day. (Adapted from U.S. Bureau of Labor Statistics)



Women’s Activities At α=0.01, can you reject the claim that the proportion of women who work is the same as the proportion of women who socialize and communicate on an average day?

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Textbook Question

Parks and Mental Health In Exercises 13–18, use the figure, which shows the percentages from a survey of two hundred 18- to 24-year-olds in the United States who say that various park and recreation activities have a positive impact on their mental health. (Adapted from National Recreation and Park Association)



Exercising and Taking Classes At α=0.01, can you reject the claim that the proportion of 18- to 24-year-olds who benefit mentally from exercising in parks is greater than or equal to the proportion who benefit mentally from taking classes in parks?

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