Variation of Hospital Times Use the sample data given in Exercise 7 “Seat Belts” and test the claim that for children hospitalized after motor vehicle crashes, the numbers of days in intensive care units for those wearing seat belts and for those not wearing seat belts have the same variation. Use a 0.05 significance level.
Table of contents
- 1. Intro to Stats and Collecting Data1h 14m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically2h 5m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables3h 6m
- 6. Normal Distribution and Continuous Random Variables2h 11m
- 7. Sampling Distributions & Confidence Intervals: Mean3h 23m
- Sampling Distribution of the Sample Mean and Central Limit Theorem19m
- Distribution of Sample Mean - Excel23m
- Introduction to Confidence Intervals15m
- Confidence Intervals for Population Mean1h 18m
- Determining the Minimum Sample Size Required12m
- Finding Probabilities and T Critical Values - Excel28m
- Confidence Intervals for Population Means - Excel25m
- 8. Sampling Distributions & Confidence Intervals: Proportion2h 10m
- 9. Hypothesis Testing for One Sample5h 8m
- Steps in Hypothesis Testing1h 6m
- Performing Hypothesis Tests: Means1h 4m
- Hypothesis Testing: Means - Excel42m
- Performing Hypothesis Tests: Proportions37m
- Hypothesis Testing: Proportions - Excel27m
- Performing Hypothesis Tests: Variance12m
- Critical Values and Rejection Regions28m
- Link Between Confidence Intervals and Hypothesis Testing12m
- Type I & Type II Errors16m
- 10. Hypothesis Testing for Two Samples5h 37m
- Two Proportions1h 13m
- Two Proportions Hypothesis Test - Excel28m
- Two Means - Unknown, Unequal Variance1h 3m
- Two Means - Unknown Variances Hypothesis Test - Excel12m
- Two Means - Unknown, Equal Variance15m
- Two Means - Unknown, Equal Variances Hypothesis Test - Excel9m
- Two Means - Known Variance12m
- Two Means - Sigma Known Hypothesis Test - Excel21m
- Two Means - Matched Pairs (Dependent Samples)42m
- Matched Pairs Hypothesis Test - Excel12m
- Two Variances and F Distribution29m
- Two Variances - Graphing Calculator16m
- 11. Correlation1h 24m
- 12. Regression3h 33m
- Linear Regression & Least Squares Method26m
- Residuals12m
- Coefficient of Determination12m
- Regression Line Equation and Coefficient of Determination - Excel8m
- Finding Residuals and Creating Residual Plots - Excel11m
- Inferences for Slope31m
- Enabling Data Analysis Toolpak1m
- Regression Readout of the Data Analysis Toolpak - Excel21m
- Prediction Intervals13m
- Prediction Intervals - Excel19m
- Multiple Regression - Excel29m
- Quadratic Regression15m
- Quadratic Regression - Excel10m
- 13. Chi-Square Tests & Goodness of Fit2h 21m
- 14. ANOVA2h 28m
10. Hypothesis Testing for Two Samples
Two Means - Known Variance
Problem 8.T.2a
Textbook Question
Take this test as you would take a test in class.For each exercise, perform the steps below.
a. Identify the claim and state and
A real estate agency says that the mean home sales price in Olathe, Kansas, is greater than in Rolla, Missouri. The mean home sales price for 39 homes in Olathe is \$392,453. Assume the population standard deviation is \$224,902. The mean home sales price for 38 homes in Rolla is \$285,787. Assume the population standard deviation is \$330,578. At α=0.05, is there enough evidence to support the agency’s claim? (Adapted from Realtor.com)
Verified step by step guidance1
Step 1: Identify the claim and state the null hypothesis \(H_0\) and the alternative hypothesis \(H_a\). The claim is that the mean home sales price in Olathe is greater than in Rolla. So, let \(\mu_1\) be the mean price in Olathe and \(\mu_2\) be the mean price in Rolla. Then, the hypotheses are:
\[
H_0: \mu_1 \leq \mu_2
\]
\[
H_a: \mu_1 > \mu_2
\]
Step 2: Determine the significance level \(\alpha\), which is given as 0.05. This will be used to decide whether to reject the null hypothesis based on the test statistic.
Step 3: Since the population standard deviations are known, and the samples are independent, use the two-sample z-test for the difference of means. Calculate the test statistic using the formula:
\[
z = \frac{(\bar{x}_1 - \bar{x}_2) - (\mu_1 - \mu_2)}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}}
\]
Here, \(\bar{x}_1 = 392,453\), \(\bar{x}_2 = 285,787\), \(\sigma_1 = 224,902\), \(\sigma_2 = 330,578\), \(n_1 = 39\), and \(n_2 = 38\). Under the null hypothesis, \(\mu_1 - \mu_2 = 0\).
Step 4: Find the critical z-value for a right-tailed test at \(\alpha = 0.05\). This value corresponds to the z-score where the area to the right is 0.05.
Step 5: Compare the calculated test statistic to the critical z-value. If the test statistic is greater than the critical value, reject the null hypothesis and conclude there is enough evidence to support the claim. Otherwise, do not reject the null hypothesis.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Hypothesis Testing
Hypothesis testing is a statistical method used to decide whether there is enough evidence to support a specific claim about a population parameter. It involves formulating a null hypothesis (no effect or difference) and an alternative hypothesis (the claim), then using sample data to determine if the null can be rejected at a given significance level (α).
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Performing Hypothesis Tests: Proportions
Two-Sample Z-Test for Means
A two-sample z-test compares the means of two independent populations when population standard deviations are known. It calculates a z-score to measure the difference between sample means relative to the variability, helping determine if the observed difference is statistically significant under the null hypothesis.
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Sampling Distribution of Sample Mean
Significance Level and P-Value
The significance level (α) is the threshold for rejecting the null hypothesis, commonly set at 0.05. The p-value measures the probability of observing the sample data, or more extreme, assuming the null is true. If the p-value is less than α, the null hypothesis is rejected, supporting the alternative claim.
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Step 3: Get P-Value
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