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Ch. 6 - Normal Probability Distributions
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 6, Problem 6.6.17a

Mendelian Genetics When Mendel conducted his famous genetics experiments with peas, one sample of offspring consisted of 929 peas, with 705 of them having red flowers. If we assume, as Mendel did, that under these circumstances, there is a 3/4 probability that a pea will have a red flower, we would expect that 696.75 (or about 697) of the peas would have red flowers, so the result of 705 peas with red flowers is more than expected.


a. If Mendel’s assumed probability is correct, find the probability of getting 705 or more peas with red flowers.

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Step 1: Identify the type of probability distribution. Since the problem involves a fixed number of trials (929 peas), two possible outcomes (red flower or not), and a constant probability of success (3/4 for red flowers), this is a binomial distribution problem.
Step 2: Define the parameters of the binomial distribution. The number of trials (n) is 929, the probability of success (p) is 3/4, and the number of successes (x) is 705 or more.
Step 3: Use the complement rule to simplify the calculation. The probability of getting 705 or more peas with red flowers is equivalent to 1 minus the probability of getting fewer than 705 peas with red flowers. Mathematically, this can be expressed as P(X ≥ 705) = 1 - P(X < 705).
Step 4: Convert the cumulative probability into a summation. For a binomial distribution, P(X < 705) is the sum of probabilities for all values of X from 0 to 704. This can be written as P(X < 705) = Σ P(X = k) for k = 0 to 704, where P(X = k) = (n choose k) * p^k * (1-p)^(n-k).
Step 5: Use a normal approximation to the binomial distribution for computational simplicity. Since n is large, the binomial distribution can be approximated by a normal distribution with mean μ = n * p and standard deviation σ = √(n * p * (1-p)). Apply the continuity correction by finding P(X ≥ 704.5) using the normal distribution formula Z = (X - μ) / σ, and calculate the corresponding probability from the standard normal table.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Probability Distribution

A probability distribution describes how the probabilities are distributed over the values of a random variable. In this context, Mendel's assumption of a 3/4 probability for red flowers suggests a binomial distribution, where each pea can be seen as a trial with two outcomes: red or not red. Understanding this distribution is crucial for calculating the likelihood of observing a specific number of successes, such as 705 red flowers.
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Calculating Probabilities in a Binomial Distribution

Binomial Probability Formula

The binomial probability formula calculates the probability of obtaining a fixed number of successes in a given number of independent Bernoulli trials. It is expressed as P(X = k) = (n choose k) * p^k * (1-p)^(n-k), where 'n' is the total number of trials, 'k' is the number of successes, and 'p' is the probability of success. This formula is essential for determining the probability of getting 705 or more red flowers in Mendel's experiment.
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Normal Approximation to the Binomial

For large sample sizes, the binomial distribution can be approximated by a normal distribution, which simplifies calculations. This approximation is valid when both np and n(1-p) are greater than 5. In Mendel's case, with 929 peas, this approximation allows for easier computation of probabilities, particularly when determining the likelihood of observing 705 or more red flowers.
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Using the Normal Distribution to Approximate Binomial Probabilities
Related Practice
Textbook Question

Using the Central Limit Theorem. In Exercises 5–8, assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of 1.2 kg and a standard deviation of 4.9 kg (based on Data Set 13 “Freshman 15” in Appendix B).


a. If 1 male college student is randomly selected, find the probability that he gains between 0.5 kg and 2.5 kg during freshman year.

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Textbook Question

Ergonomics. Exercises 9–16 involve applications to ergonomics, as described in the Chapter Problem.


Safe Loading of Elevators The elevator in the car rental building at San Francisco International Airport has a placard stating that the maximum capacity is “4000 lb—27 passengers.” Because 4000/27=148, this converts to a mean passenger weight of 148 lb when the elevator is full. We will assume a worst-case scenario in which the elevator is filled with 27 adult males. Based on Data Set 1 “Body Data” in Appendix B, assume that adult males have weights that are normally distributed with a mean of 189 lb and a standard deviation of 39 lb.


a. Find the probability that 1 randomly selected adult male has a weight greater than 148 lb.

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Textbook Question

Using the Central Limit Theorem. In Exercises 5–8, assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of 1.2 kg and a standard deviation of 4.9 kg (based on Data Set 13 “Freshman 15” in Appendix B).

a. If 1 male college student is randomly selected, find the probability that he gains between 0 kg and 3 kg during freshman year.

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Textbook Question

Body Temperatures Listed below are body temperatures (°F) of adult males (based on Data Set 5 “Body Temperatures” in Appendix B).


97.6 98.2 99.6 98.7 99.4 98.2 98.0 98.6 98.6


a. Find the mean. Does the result seem reasonable?

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Textbook Question

Transformations The heights (in inches) of women listed in Data Set 1 “Body Data” in Appendix B have a distribution that is approximately normal, so it appears that those heights are from a normally distributed population.


a. If 2 inches is added to each height, are the new heights also normally distributed?

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Textbook Question

Smartphones Based on an LG smartphone survey, assume that 51% of adults with smartphones use them in theaters. In a separate survey of 250 adults with smartphones, it is found that 109 use them in theaters.


a. If the 51% rate is correct, find the probability of getting 109 or fewer smartphone owners who use them in theaters.

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