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Multiple Choice
Suppose a population has a mean of and a standard deviation of . What is the z-score for a value of ? Round your answer to two decimal places as needed.
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Identify the given values: the population mean \( \mu = 50 \), the population standard deviation \( \sigma = 8 \), and the value for which you want to find the z-score \( X = 66 \).
Recall the formula for the z-score, which measures how many standard deviations a value is from the mean:
\[ Z = \frac{X - \mu}{\sigma} \]
Substitute the given values into the formula:
\[ Z = \frac{66 - 50}{8} \]
Calculate the numerator (the difference between the value and the mean) and then divide by the standard deviation to find the z-score.
Interpret the z-score as the number of standard deviations the value 66 is above the mean of 50.